Definition:
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Two events, A and B, are independent if the fact that
A occurs does not affect the probability of B occurring.
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Some other examples of independent events are:
- Landing
on heads after tossing a coin AND rolling a 5 on a single
6-sided die.
- Choosing
a marble from a jar AND landing on heads after tossing a
coin.
- Choosing
a 3 from a deck of cards, replacing it, AND then choosing
an ace as the second card.
- Rolling
a 4 on a single 6-sided die, AND then rolling a 1 on a second
roll of the die.
A card is chosen at random from a deck of 52 cards.
It is then replaced and a second card is chosen. What is the probability of
choosing a jack and then an eight?
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DEPENDENT
EVENT PROPERTIES
Definition:
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Two events are dependent if the outcome or occurrence
of the first affects the outcome or occurrence of the second so that the
probability is changed.
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Now that we have accounted for the fact that there is no replacement,
we can find the probability of the dependent events in Experiment 1 by
multiplying the probabilities of each event.
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Experiment 1:
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A card is chosen at random from a standard deck of 52 playing cards.
Without replacing it, a second card is chosen. What is the probability that
the first card chosen is a queen and the second card chosen is a jack?
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Probabilities:
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MUTUALLY EXCLUSIVE
EVENTS
Two events are mutually exclusive if they cannot occur
at the same time.
Examples
- When
tossing a fair coin, the event 'getting a head' and the event 'getting a
tail' are mutually exclusive because they can't occur at the same time.
- When
throwing a fair die, the event 'getting a 1' and the event 'getting a 4'
are mutually exclusive because they can't occur at the same time. But the
event 'getting a 3' and the event 'getting an odd number' are not mutually
exclusive since it can happen at the same time (i.e. if you get 3)
For two mutually exclusive events, A and B,
the probability of either one occurring, P(A or B),
is the sum of the probability of each event.
P(A or B)
= P(A) + P(B)
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For example, when choosing a ball at random from a bag containing 3 blue balls, 2 green bals, and 5 red balls, the probability of getting a blue or red ball is
P(Blue or Red)
= P(Blue) + P(Red)
P(Blue or Red)
= 3/10 + 5/10
P(Blue or Red)
= 8/10 = 0.8
This is so because a card can either be red, king, or both (i.e. red
king). So that's why we need to subtract the probability of a card being both
red and king because it has already been accounted for in the probability of
the card being red and the probability of the card being king.
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